36-27x^2=0

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Solution for 36-27x^2=0 equation:



36-27x^2=0
a = -27; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-27)·36
Δ = 3888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3888}=\sqrt{1296*3}=\sqrt{1296}*\sqrt{3}=36\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{3}}{2*-27}=\frac{0-36\sqrt{3}}{-54} =-\frac{36\sqrt{3}}{-54} =-\frac{2\sqrt{3}}{-3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{3}}{2*-27}=\frac{0+36\sqrt{3}}{-54} =\frac{36\sqrt{3}}{-54} =\frac{2\sqrt{3}}{-3} $

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